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If you freeze time at, say, t = 446.00, the voltage is zero. Looking at the diagram, you can see that the voltage will also be zero every so-many-and-a-half seconds, so it will be zero at t = 446.5. But instead of getting more positive at these instants, the voltage will be negative-going. If you freeze time at so-many-and-a-quarter seconds, say t = 446.25, the voltage will be +1 V. The wave will be exactly at its positive peak. If you stop time at so-many-and-three-quarter seconds, say t = 446.75, the voltage will be exactly at its negative peak, 1 V. At intermediate times, say, somany-and-three-tenths seconds, the voltage will have intermediate values.

A capacitor is rated at 0.001 F, plus-or-minus 10 percent. What is the actual range of capacitances it can have First, multiply 0.001 by 10 percent to get the plus-or-minus variation. This is 0.001 0.1 0.0001 F. Then add and subtract this from the rated value to get the maximum and minimum possible capacitances. The result is 0.0011 F to 0.0009 F. You might prefer to work with picofarads instead of microfarads, if the small numbers make you feel uneasy. Just change 0.001 F to 1000 pF. Then the variation is plus-or-minus 1000 0.1 100 pF, and the range becomes 1100 pF to 900 pF.

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After Iridium, the best-known LEO satellite services company is Teledesic. Started in 1990 by Craig McCaw and Bill Gates, Teledesic will comprise an array of 288 satellites capable of providing up to 64 Mbps downstream and 2 Mbps upstream for voice, videoconferencing, and data, with plans in place to offer symmetric 64-Mbps service sometime in the future. In 1998, Motorola joined the Teledesic team, and in 1999 the company signed a launch agreement with Lockheed Martin. They plan to be fully operational by 2005.

Figure 12-1 shows that there are times the voltage is increasing, and times it is decreasing. Increasing, in this context, means getting more positive, and decreasing means getting more negative. The most rapid increase in voltage occurs when t = 0.0 and t = 1.0. The most rapid decrease takes place when t = 0.5. When t = 0.25, and also when t = 0.75, the instantaneous voltage neither increases nor decreases. But this condition exists only for a vanishingly small moment, a single point in time. Suppose n is some whole number. Then the situation at t = n.25 is the same as it is for t = 0.25; also, for t = n.75, things are the same as they are when t = 0.75. The single cycle shown in Fig. 12-1 represents every possible condition of the ac sine wave having a frequency of 1 Hz and a peak value of 1 V. The whole wave recurs, over and over, for as long as the ac continues to flow in the circuit. Now imagine that you want to observe the instantaneous rate of change in the voltage of the wave in Fig. 12-1, as a function of time. A graph of this turns out to be a sine wave, too but it is displaced to the left of the original wave by 1 4 of a cycle. If you plot the instantaneous rate of change of a sine wave against time (Fig. 12-2), you get the derivative of the waveform. The derivative of a sine wave is a cosine wave. This wave has the same shape as the sine wave, but the phase is different by 1 4 of a cycle.

Some capacitors increase in value as the temperature increases. These components have a positive temperature coefficient. Some capacitors values get less as the temperature rises; these have negative temperature coefficient. Some capacitors are manufactured so that their values remain constant over a certain temperature range. Within this span of temperatures, such capacitors have zero temperature coefficient. The temperature coefficient is specified in percent per degree Celsius. Sometimes, a capacitor with a negative temperature coefficient can be connected in series or parallel with a capacitor having a positive temperature coefficient, and the two opposite effects will cancel each other out over a range of temperatures. In other instances, a capacitor with a positive or negative temperature coefficient can be used to cancel out the effect of temperature on other components in a circuit, such as inductors and resistors. You won t have to do calculations involving temperature coefficients if you re in a management position; you can delegate these things to the engineers. If you plan to become an engineer, you ll most likely have computer software that will perform the calculations for you.

voltage of the wave shown in Fig. 12-1.

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