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Buffering I/O is a very common performance optimization Java's BufferedInputStream class allows you to "wrap" any InputStream into a buffered stream and achieve this performance improvement BufferedInputStream has two constructors: BufferedInputStream(InputStream inputStream) BufferedInputStream(InputStream inputStream, int bufSize) The first form creates a buffered stream using a default buffer size In the second, the size of the buffer is passed in bufSize Use of sizes that are multiples of memory page, disk block, and so on can have a significant positive impact on performance This is, however, implementation-dependent An optimal buffer size is generally dependent on the host operating system, the amount of memory available, and how the machine is configured To make good use of buffering doesn't necessarily require quite this degree of sophistication A good guess for a size is around 8,192 bytes, and attaching even a rather small buffer to an I/O stream is always a good idea That way, the low-level system can read blocks of data from the disk or network and store the results in your buffer Thus, even if you are reading the data a byte at a time out of the InputStream, you will be manipulating fast memory over 999 percent of the time Buffering an input stream also provides the foundation required to support moving backward in the stream of the available buffer Beyond the read( ) and skip( ) methods implemented in any InputStream, BufferedInputStream also supports the mark( ) and reset( ) methods This support is reflected by BufferedInputStreammarkSupported( ) returning true The following example contrives a situation where we can use mark( ) to remember where we are in an input stream and later use reset( ) to get back there This example is parsing a stream for the HTML entity reference for the copyright symbol Such a reference begins with an ampersand (&) and ends with a semicolon (;) without any intervening whitespace The sample input has two ampersands to show the case where the reset( ) happens and where it does not // Use buffered input import javaio*; class BufferedInputStreamDemo {.

Thus, as noted in Sec 123, the Gibbs-energy change of mixing must always be negative, and a plot of AG vs xl for a binary system must appear as shown by one of the curves of Fig 1411 With respect to curve 1 , however, there is a further consideration If, when mixing occurs, a 1 system can achieve a lower value of the Gibbs energy by forming two phases than by forming a single phase, then the system splits into two phases This is in fact the situation represented between points a and B on curve I1 of Fig 1411, because the straight dashed line connecting points a and B represents the AG that would obtain for the range of states consisting of two phases of compositions x;Y and xf in various proportions Thus the solid curve shown between points a and p cannot represent stable phases with respect to phase splitting The equilibrium states between a and ,f consist of two phases These considerations lead to the following criterion of stability for a single-phase binary system:

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4:

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At constant temperature and pressure, A G and its first and second derivatives must be continuous functions of XI, and the second derivative must everywhere be positive

At first blush there is nothing wrong, but it turns out the id value is used twice, as demonstrated here:

public static void main(String args[]) throws IOException { String s = "This is a © copyright symbol " + "but this is © not\\n"; byte buf[] = sgetBytes(); ByteArrayInputStream in = new ByteArrayInputStream(buf); BufferedInputStream f = new BufferedInputStream(in); int c; boolean marked = false; while ((c = fread()) != -1) { switch(c) { case '&': if (!marked) { fmark(32); marked = true; } else { marked = false; } break; case ';': if (marked) { marked = false; Systemoutprint("(c)"); } else Systemoutprint((char) c); break; case ' ': if (marked) { marked = false; freset(); Systemoutprint("&"); } else Systemoutprint((char) c); break; default: if (!marked) Systemoutprint((char) c); break; } }

<!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <title>CSS Validation Challenges</title> <style type="text/css"> #unique {color: red; font-size: xx-large;} </style> </head> <body> <p id="unique">I am the paragraph with id unique</p> <p>I am not the unique paragraph</p> <p id="unique">Yet another unique paragraph </p> </body> </html>

Thus, d 2 AG >0 dx: (const T, P )

If this document is CSS validated, everything is apparently okay:

Notice that this example uses mark(32), which preserves the mark for the next 32 bytes read (which is enough for all entity references) Here is the output produced by this program: This is a (c) copyright symbol but this is © not Caution Use of mark( ) is restricted to access within the buffer This means that you can only specify a parameter to mark( ) that is smaller than the buffer size of the stream

However, with HTML validation we see that is actually not the case:

(const T, P )

A BufferedOutputStream is similar to any OutputStream with the exception of an added flush( ) method that is used to ensure that data buffers are physically written to the actual output device Since the point of a BufferedOutputStream is to improve performance by reducing the number of times the system actually writes data, you may need to call flush( ) to cause any data that is in the buffer to get written

Part II:

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Again, visually we may get the desired effect of two large red paragraphs, but it isn t executed correctly and we will potentially pay a price later with JavaScript, which typically does not allow the same latitude that presentational technologies do Consider simply that each layer of technology we add on with small mistakes makes the overall execution shakier and shakier Given this foundational approach, we should first validate markup and then, once it is solid, validate the CSS that is layered on top

This requirement has a number of consequencesEquation (1230),rearranged and written for a binary system, becomes:

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