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This system will have minimum phase if the zeros of A(z) are inside this unit circle. Although this could be determined by factoring A(z), because the reflection coefficients used to generate A ( : ) are bounded by I In magnitude. it follows that A ( z ) has minimum phase.

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If t < sk , do steps 4 6 4 Set si = sk 5 Set i = k 6 If i < n/2 and si < max{s2i+1, s2i+2}, repeat steps 1 4 7 Set sk = t There are two aspects to these algorithms that distinguish them from the methods outlined in 12 The heaps here are in the reverse order, so each root-to-leaf path is descending And these algorithms use 0-based indexing The reverse order guarantees that heapify will always leave the largest element at the root of the subsequence Using 0-base indexing instead of 1based indexing renders the sort() method consistent with all the other sort() methods at the expense of making the code a little more complicated EXAMPLE 1410 The Heap Sort.

( b ) The system function A'(z) = G(-.)/X ( z ) is related to X ( z ) as follows:

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public static void sort(int[] a) { // POSTCONDITION: a[0] <= a[1] <= ... <= a[a.length-1]; sort(a, 0, a.length); } private static void sort(int[] a, int p, int q) { // PRECONDITION: 0 <= p <= q <= a.length // POSTCONDITION: a[p..q) is sorted; if (q - p < 2) { return; } int m = partition(a, p, q); // step 2 sort(a, p, m); // step 4 sort(a, m+1, q); // step 5 } private static int partition(int[] a, int p, int q) { // RETURNS: index m of pivot element a[m]; // POSTCONDITION: a[i] <= a[m] <= a[j] for p <= i <= m <= j < q; int pivot = a[p], i = p, j = q; // steps 1-2 while (i < j) { // step 3 while (i < j && a[--j] >= pivot) ; // step 4 if (i < j) { a[i] = a[j]; // step 5 } while (i < j && a[++i] <= pivot) ; // step 6 if (i < j) { a[j] = a[i]; // step 7 } } a[j] = pivot; // step 8 return j; }

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all Because the zeros of A1(z)are formed by flipping the zeros of A ( )about the unit c~rcle. of the zeros of A'(:) will be o~ctside unit circle and thus will not have minimum phase. the

34 35 36 37 38 39

( a ) Find the zeros of the system function A ( z ) .

Note the empty loop at line 22 and line 26. All the action is managed within the loop condition, so no statements are in its body.

r3= - 1 .

public static void sort(int[] a) { // POSTCONDITION: a[0] <= a[1] <= ... <= a[a.length-1]; int n = a.length; for (int i = n/2 - 1; i >= 0; i--) { // step 1 heapify(a, i, n); // step 2 }

Algorithm 14.7 selects the pivot element to be the last element in the sequence. The algorithm works just as well if it is selected to be the first element or the middle element. Slightly better performance is obtained by selecting the median of those three elements. The Java Arrays.sort() method implements the quick sort, selecting the pivot as the median of the three elements {s0, sn/2, sn 1} when n 40, and the median of 9 equally spaced elements when n > 40. It also switches to the insertion sort (Algorithm 14.3 on page 258) when n < 7.

for j = 1,2, ... . p - 1

( a ) To find the system function A ( z ) for a given set of reflection coefficients, we use the step-up recursion. For a l ( k )we have

CHAP. 14]

A(z) = 1

+ + z - ' + t ~+ z-3 ~ fi3 = C-~().JM6"

40 41 42 43 44 45

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