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By the way, here is the same code as a #define macro directive (yes, all the brackets are needed): #define min(a,b) ((a) < (b)) (a) : (b) Then you use the template just as you would any other function: int a = 5; int b = 6; Console::WriteLine("The min of {0} and {1} is {2}", a, b, min(a,b)); The compiler will look at the function min and check to see if the data types are the same. If they are, it will generate an instance of a function to handle the function. For example, if a and b are int values, then code similar to the following will be generated: int min ( int a, int b) { return (a < b) a : b; } Be careful, though, because the template specifies that the data type of both parameters must be the same, given that only one type is specified within the template. If you were to implement the preceding template like this: int a = 5; double b = 6; Console::WriteLine("The min of {0} and {1} is {2}", a, b, min(a,b)); the compiler would generate an error, as it would not be able to resolve the template type. Templates allow you to specify multiple template types. You could go wild and instead declare the preceding template to support different data types, like this: template <class T1, class T2> T1 min ( T1 a, T2 b) { return (T1)((a < b) a : b); } Then if you implemented the template using different data types, you would be fine. Or would you What happens if the type data types in the template could not be compared For example, what would happen if the first data type was an int and the second a handle to String

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int a = 5; String^ b = "Hi"; Console::WriteLine("The min of {0} and {1} is {2}", a, b, min(a,b)); The types are compared at compile time and will be found to be incompatible, and a compile-time error will be generated. All the preceding implementation of the template functions has been implicit. It is also possible to implement the template explicitly. This is done by specifying the data type to use in square brackets after the function name within the function call. Now, because there is no longer any ambiguity of the data type being used, the explicit instantiation of the original min function template would compile. int a = 5; double b = 6; Console::WriteLine("The min of {0} and {1} is {2}", a, b, min<double>(a,b));

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The idea behind class templates is the same as function templates. This time, though, the template creates data type generic classes. Syntactically, the declaration of a class template is the same as a standard class, except that you prefix the class with a template statement and then use the data type specified by the prefix within the class declaration. template <class T> ref class Point2D { public: Point2D(); T X; T Y; static Point2D^ operator*(const Point2D^ lhs, const T rhs); }; The implementation of the template is a little more involved, as you need to also prefix the methods with the template statement and qualify the method with the class template followed by a template argument list. One thing I find a little odd about the class template implementation is that you don t need a template argument list when you use a template class within a method, but if you return a template class, you do. Take a closer look at the operator* method to see what I mean: template <class T> Point2D<T>::Point2D() : X((T)0), Y((T)0) {} template <class T> Point2D<T>^ Point2D<T>::operator*(const Point2D^ lhs, const T rhs) { Point2D^ ret = gcnew Point2D(); ret->X = lhs->X * rhs; ret->Y = lhs->Y * rhs; return ret; } Creating an instance of a class template is nearly as easy as creating an instance of a class. You simply need to explicitly specify the data type to be used by the template when you create the instance of the template class using a template argument list: Point2D<double>^ TopLeft = gcnew Point2D<double>(10.5, 10.9);

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