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The object passed to arg is automatically passed to the thread s entry point method Thus, to pass an argument to a thread, you pass it to Start( ) To make use of the parameterized version of Start( ), you must use the following form of the Thread constructor: public Thread(ParameterizedThreadStart entryPoint) Here, entryPoint is the name of the method that will be called to begin execution of the thread Notice in this version, the type of entryPoint is ParameterizedThreadStart rather than ThreadStart, as used by the preceding examples ParameterizedThreadStart is a delegate that is declared as shown here: public delegate void ParameterizedThreadStart(object arg) As you can see, this delegate takes an argument of type object Therefore, to use this form of the Thread constructor, the thread entry point method must have an object parameter Here is an example that demonstrates the passing of an argument to a thread:

Equating the two expressions for slope, we nd that 3 y 5 = x+4 10 Simplifying this identity, we nd that the equation of our line is 3 (x + 4) 10 You Try It: Find the equation of the line that passes through the points (2, 5) and ( 6, 1) y 5= In general, the line that passes through points (x0 , y0 ) and (x1 , y1 ) has equation y1 y0 y y0 = x x0 x1 x0 This is called the two-point form of the equation of a line EXAMPLE 112

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// Passing an argument to the thread method using System; using SystemThreading; class MyThread { public int Count; public Thread Thrd; // Notice that MyThread is also passed an int value public MyThread(string name, int num) { Count = 0; // Explicitly invoke ParameterizedThreadStart constructor // for the sake of illustration Thrd = new Thread(thisRun); ThrdName = name; // Here, Start() is passed num as an argument ThrdStart(num); }

[ p] = [ N (f 2 )]-1 [ S1 (f 2 , s2 )] [ M ( s2 )]-1

Part II:

// Notice that this version of Run() has // a parameter of type object void Run(object num) { ConsoleWriteLine(ThrdName + " starting with count of " + num); do { ThreadSleep(500); ConsoleWriteLine("In " + ThrdName + ", Count is " + Count); Count++; } while(Count < (int) num); ConsoleWriteLine(ThrdName + " terminating"); } } class PassArgDemo { static void Main() { // Notice that the iteration count is passed // to these two MyThread objects MyThread mt = new MyThread("Child #1", 5); MyThread mt2 = new MyThread("Child #2", 3); do { ThreadSleep(100); } while (mtThrdIsAlive | mt2ThrdIsAlive); ConsoleWriteLine("Main thread ending"); } }

Find the line perpendicular to y = 3x 6 that passes through the point (5, 4)

7 Evaluate the complete follower motion function by applying Eq (547) After the follower motion function is determined, kinematic properties for the velocity v1 (f2, s2), the acceleration A1 (f2, s2), and the jerk J1 (f2, s2) of the synthesized follower motion can be derived by differentiating Eq (537) When the angular and linear velocities of the cam are constant, the derivatives can be expressed as

The output is shown here (The actual output you see may vary)

Child #1 starting with count of 5 Child #2 starting with count of 3 In Child #2, Count is 0 In Child #1, Count is 0 In Child #1, Count is 1 In Child #2, Count is 1 In Child #2, Count is 2 Child #2 terminating In Child #1, Count is 2 In Child #1, Count is 3 In Child #1, Count is 4 Child #1 terminating Main thread ending

v1 (f 2 , s2 ) =

As the output shows, the first thread iterates five times and the second thread iterates three times The iteration count is specified in the MyThread constructor and then passed to the thread entry method Run( ) through the use of the ParameterizedThreadStart version of Start( )

SOLUTION We know from the Math Note immediately after Example 110 that the given line has slope 3 Thus the line we seek (the perpendicular line) has slope 1/3 Using the point-slope form of a line, we may immediately write the equation of the line with slope 1/3 and passing through (5, 4) as y 4= 1 (x 5) 3

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