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package { import flash.display.Sprite; import flash.events.MouseEvent; import flash.filters.ColorMatrixFilter; public class ch37ex9 extends Sprite { protected var img:TestImage; function ch37ex9() { img = new TestImage(); addChild(img);

Since 0.05 and n1 n2 10, Appendix Table IX gives the critical value as w0.05 78. If either w1 or w2 is less than or equal to w0.05 78, we will reject H0: 1 2.

if (magorigin =- 0) I rootLog += nag. message 0 + "\n" ; rootLogArea.setText(rootLog); case CUIHessage . CUIH-RCV : case CUIMessage.CUIM-XMIT: m-messageLogger.addLog(msg0rigin. break ; case GUIHessage.CUIM-NODESTATE: break ;

EXAMPLE 37-9

Table 15-3 Axial Stress for Two Aluminum-Lithium Alloys Alloy 1 238 psi 3195 3246 3190 3204 3254 psi 3229 3225 3217 3241 3261 psi 3187 3209 3212 3258 Alloy 2 3248 psi 3215 3226 3240 3234

(continued)

Computations: The data from Table 15-3 are analyzed in ascending order and ranked as follows:

Alloy Number 2 1 1 1 2 2 2 1 1 2 1 2 1 2 1 1 2 1 2 2 Axial Stress 3187 psi 3190 3195 3204 3209 3212 3215 3217 3225 3226 3229 3234 3238 3240 3241 3246 3248 3254 3258 3261 Rank 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

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addEventListener(MouseEvent.MOUSE_MOVE, onMouseMove); } protected function onMouseMove(event:MouseEvent):void { //1 for no change, 0 for lowest contrast, 2 and up for high contrast var contrastAmount:Number; //mouse at left for lowest contrast, right for 3x contrast boost contrastAmount = stage.mouseX / stage.stageWidth * 3; var scale:Number = contrastAmount; var offset:Number = 128 * (1 - scale); var aContrast:Array = [scale, 0, 0, 0, offset, 0, scale, 0, 0, offset, 0, 0, scale, 0, offset, 0, 0, 0, 1, 0]; img.filters = [new ColorMatrixFilter(aContrast)]; } } } import flash.display.Loader; import flash.net.URLRequest; import flash.system.LoaderContext; class TestImage extends Loader { public function TestImage(scale:Number = 1, x:Number = 0, y:Number = 0) { //photo (CC-BY) Roger Braunstein //source http://www.flickr.com/photos/rogerimp/2940373537/ var url:String = "http://actionscriptbible.com/files/heiwadoori.jpg"; load(new URLRequest(url), new LoaderContext(true)); scaleX = scaleY = scale; this.x = x; this.y = y; } }

The sum of the ranks for alloy 1 is w1 and for alloy 2 n2 21n1 n2 12 110 102110 10 12 w1 99 111 2 2 Conclusions: Since neither w1 nor w2 is less than or equal to w0.05 78, we cannot reject the null hypothesis that both alloys exhibit the same mean axial stress. w2 1n1 2 3 4 8 9 11 13 15 16 18 99

You can design a matrix that will remove all color from an image. Try deriving it from rst principles. Shades of gray contain equal amounts of red, green, and blue: black has 0 of each, 50 percent gray has 128 of each (0x808080, 0x80 = 128), and white has 255 of each (0xFFFFFF, 0xFF = 255). So one property of the matrix is that all the equations to determine red, green, and blue channels must be the same, to ensure the output is equal. In matrix terms, this means the rst three rows should be identical. In a grayscale image, there is no hue. There is only the relative lightness or darkness of the pixel. So if you wanted to convert a color image to grayscale, the color of the output pixel should be related to the brightness of the input pixel. A good way to do this is to average the RGB channels. So every gray value is determined by an equal weighting of the brightness of the three color channels. This leads to the simple equation:

15-4.2

Or, in matrix form:

When both n1 and n2 are moderately large, say, greater than 8, the distribution of w1 can be well approximated by the normal distribution with mean n1 1n1 n2 2 12

However, brains are wired to perceive visual reality in a subjective manner. Anyone who s looked at optical illusions knows how subjective vision is. Sometimes what is mathematically precise is not what looks the best. Remember in 35, Programming Vector Graphics, that the default blending mode for gradients is not linear through RGB there, the blending mode that looks best isn t the most mathematically precise. Likewise, you can make a better-looking grayscale image by choosing nonequal bias for each of the red, green, and blue channels. Choosing biases, or luminance coef cients, of 0.3086, 0.6094, and 0.0820, respectively, yields a more natural-looking image. This matrix encodes the constants:

2 W1

n2 12

EXAMPLE 37-10

(15-8)

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